Finding Area by the Limit Definition
The area of a plane region (i.e., a 2-D shape) between the graph of a function and the x-axis can be found using the limit definition:
The formula looks complicated, but all you have to do is substitute in your values for the function ( f ) and interval ( b – a ). From there, you can simplify and solve.
Finding Area by the Limit Definition: Example
Example question: Find the area (using the limit definition) between f(x) = 2x^{3} – x^{2} and the x-axis, on the interval [1, 2].
Step 1: (Optional) Make a graph. This not only gives you a visual of what you are trying to find, but you can ballpark your solution to see if your calculated answer makes sense.
Step 2: Find f (c_{i}) by substituting in your interval (a and b) values into the f(c_{i}) formula given above. We are finding the area for the interval between 1 and 2, so substituting those in and simplifying gives us:
Step 3: Find Δx by substituting your a and b values into the Δx formula from above:
Step 4: Substitute your answers from Step 2 and Step 3 into the main limit definition formula from above:
Step 5: Change the generic “f(x)” part of the formula (from Step 4) to your actual function and simplify. Our function for this example is f(x) = 2x^{3} – x^{2}, so:
Multiplying (1/n) through each term:
Step 6: Distribute the summation symbol through all terms in your answer from Step 5:
Step 7: Apply summation properties and simplify.
Term | Summation |
i^{3} | |
i^{2} | |
i | |
c |
Step 8: Find the limit of all the “parts” from Step 7. For this example, we need one property of limits, which is the limit (1/x) = 0 (as x→∞) is 0:
Area = 0 + 0 + 1 + (1/2) + (5/3) + 2 = (31/6).
The solution is 31/6 ≈ 5.167.
References
Graph created with Desmos.com.
Question from Calculus of a Single Variable, 10th edition. 4.2 Exercises, page 264.
Stephanie Glen. "Finding Area by the Limit Definition" From CalculusHowTo.com: Calculus for the rest of us! https://www.calculushowto.com/finding-area-by-the-limit-definition/
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